Drop and Recreate all indexes

I have a need to drop and then recreate all indexes in a database. I have tried DBCC DBREINDEX to clean up fragmentation, but now I have been asked to drop and recreate all indexes. Is there a script out there that can do this. I need the script if it exists. I am a newbie and not very good at coding SQL yet.

You can make use of the following script from MS...

-- Ensure a USE <databasename> statement has been executed first.
SET NOCOUNT ON;
DECLARE @objectid int;
DECLARE @indexid int;
DECLARE @partitioncount bigint;
DECLARE @schemaname nvarchar(130);
DECLARE @objectname nvarchar(130);
DECLARE @indexname nvarchar(130);
DECLARE @partitionnum bigint;
DECLARE @partitions bigint;
DECLARE @frag float;
DECLARE @command nvarchar(4000);
-- Conditionally select tables and indexes from the sys.dm_db_index_physical_stats function
-- and convert object and index IDs to names.
SELECT
object_id AS objectid,
index_id AS indexid,
partition_number AS partitionnum,
avg_fragmentation_in_percent AS frag
INTO #work_to_do
FROM sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL , NULL, 'LIMITED')
WHERE avg_fragmentation_in_percent > 10.0 AND index_id > 0;

-- Declare the cursor for the list of partitions to be processed.
DECLARE partitions CURSOR FOR SELECT * FROM #work_to_do;

-- Open the cursor.
OPEN partitions;

-- Loop through the partitions.
WHILE (1=1)
BEGIN;
FETCH NEXT
FROM partitions
INTO @objectid, @indexid, @partitionnum, @frag;
IF @@FETCH_STATUS < 0 BREAK;
SELECT @objectname = QUOTENAME(o.name), @schemaname = QUOTENAME(s.name)
FROM sys.objects AS o
JOIN sys.schemas as s ON s.schema_id = o.schema_id
WHERE o.object_id = @objectid;
SELECT @indexname = QUOTENAME(name)
FROM sys.indexes
WHERE object_id = @objectid AND index_id = @indexid;
SELECT @partitioncount = count (*)
FROM sys.partitions
WHERE object_id = @objectid AND index_id = @indexid;

-- 30 is an arbitrary decision point at which to switch between reorganizing and rebuilding.
IF @frag < 30.0
SET @command = N'ALTER INDEX ' + @indexname + N' ON ' + @schemaname + N'.' + @objectname + N' REORGANIZE';
IF @frag >= 30.0
SET @command = N'ALTER INDEX ' + @indexname + N' ON ' + @schemaname + N'.' + @objectname + N' REBUILD';
IF @partitioncount > 1
SET @command = @command + N' PARTITION=' + CAST(@partitionnum AS nvarchar(10));
EXEC (@command);
PRINT N'Executed: ' + @command;
END;

-- Close and deallocate the cursor.
CLOSE partitions;
DEALLOCATE partitions;

-- Drop the temporary table.
DROP TABLE #work_to_do;
GO

Wait, AFAIK, DBCC DBREINDEX drops and recreates the indexes internally.

Roji. P. Thomas
http://toponewithties.blogspot.com

this tool will create drop/create scripts for all objects, including indexes, with a separate file for each.

http://www.sql-server-performance.com/forum/topic.asp?TOPIC_ID=17482

it would be a simple matter to write a .bat file to execute each generated file using osql/sqlcmd.



SqlSpec - a fast, cheap, and comprehensive data dictionary generator
for SQL Server 2000 and 2005 and Analysis Server 2005 - www.elsasoft.org

Some people think drop and create will give better improvement than REINDEX<img src='/community/emoticons/emotion-1.gif' alt='' /><br /><br />If the clustered index is not unique then only non-clustered indexes gets recreated other wise it create only clustered index.<br /><br />Mohammed.