Error Message:
Msg 4448, Level 16, State 17, Line 2
Cannot INSERT into partitioned view ‘%.*ls’ because values were not supplied for all columns.
Severity level:
16.
Description:
This error message appears when you try to insert into a partitioned view but do not provide values for all columns.
Consequences:
The T-SQL statement can be parsed, but causes the error at runtime.
Resolution:
Errors of the Severity Level 16 are generated by the user and can be fixed by the SQL Server user. The statement cannot be executed this way. You must provide values for all columns.
Versions:
This error message was introduced with SQL Server 2000.
Example(s):
IF OBJECT_ID (‘dbo.T’) IS NOT NULL
DROP TABLE dbo.T;
GO
IF OBJECT_ID (‘dbo.T1’) IS NOT NULL
DROP TABLE dbo.T1;
GO
IF OBJECT_ID (‘dbo.V’) IS NOT NULL
DROP VIEW dbo.V;
GO
CREATE TABLE dbo.T
(
c1 int PRIMARY KEY CHECK (c1 BETWEEN 1 AND 10),
c2 int
)
GO
CREATE TABLE dbo.T1
(
c1 int PRIMARY KEY CHECK (c1 BETWEEN 11 AND 20),
c2 int
)
GO
CREATE VIEW dbo.V
AS
SELECT
c1, c2
FROM
dbo.T
UNION ALL
SELECT
c1, c2
FROM
dbo.T1;
GO
INSERT INTO dbo.V (c1) VALUES (1);
Remarks:
In the above example we try to insert into the view dbo.V. Because we have not supplied a value for the column c2, the error is raised.